# Difference between revisions of "TADM2E 2.19"

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(Recovering wiki) |
Kelvinjhwong (Talk | contribs) (Changed "({3}/{2})^n = 2^n" to "({3}/{2})^n < 2^n") |
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Line 13: | Line 13: | ||

n^3 < | n^3 < | ||

n - n^3 + 7n^5 < | n - n^3 + 7n^5 < | ||

− | ({3}/{2})^n | + | ({3}/{2})^n < 2^n < |

n! | n! | ||

</math> | </math> |

## Latest revision as of 06:14, 27 November 2018

$ ({1}/{3})^n < 6 < \log \log n < \log n = \ln n < (\log n)^2 < n^{\frac{1}{3}} + \log n < \sqrt{n} < \frac{n}{\log n}< n < n \log n < n^2 = n^2 + \log n < n^3 < n - n^3 + 7n^5 < ({3}/{2})^n < 2^n < n! $