# TADM2E 3.12

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Revision as of 18:22, 11 September 2014 by Algowikiadmin (Talk | contribs)

Let's put into the black box whole set $ S=\{x_i\}_{i=1}^n $. If $ bb(S) $ is True, then such subset existing and we can go on:

- R:=S
- for i:=1 to n do
- If $ bb(R/\{x_i\}) $ is True then $ R:=R/\{x_i\} $

When this iteration is finished R will be subset of S that adds up to k.