Difference between revisions of "Chapter 2"
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− | :2.8 | + | :2.8. #Is <math>2^{n+1} = O (2^n)</math>? |
+ | #Is <math>2^{2n} = O(2^n)</math>? | ||
− | |||
− | :2.10 | + | :[[2.9]]. For each of the following pairs of functions, either <math>f(n )</math> is in <math>O(g(n))</math>, <math>f(n)</math> is in <math>\Omega(g(n))</math>, or <math>f(n)=\Theta(g(n))</math>. Determine which relationship is correct and briefly explain why. |
+ | #<math>f(n)=\log n^2</math>; <math>g(n)=\log n</math> + <math>5</math> | ||
+ | #<math>f(n)=\sqrt n</math>; <math>g(n)=\log n^2</math> | ||
+ | #<math>f(n)=\log^2 n</math>; <math>g(n)=\log n</math> | ||
+ | #<math>f(n)=n</math>; <math>g(n)=\log^2 n</math> | ||
+ | #<math>f(n)=n \log n + n</math>; <math>g(n)=\log n</math> | ||
+ | #<math>f(n)=10</math>; <math>g(n)=\log 10</math> | ||
+ | #<math>f(n)=2^n</math>; <math>g(n)=10 n^2</math> | ||
+ | #<math>f(n)=2^n</math>; <math>g(n)=3^n</math> | ||
− | :2.11 | + | [[2.11|Solution]] |
+ | |||
+ | |||
+ | :2.10. For each of the following pairs of functions <math>f(n)</math> and <math>g(n)</math>, determine whether <math>f(n) = O(g(n))</math>, <math>g(n) = O(f(n))</math>, or both. | ||
+ | #<math>f(n) = (n^2 - n)/2</math>, <math>g(n) =6n</math> | ||
+ | #<math>f(n) = n +2 \sqrt n</math>, <math>g(n) = n^2</math> | ||
+ | #<math>f(n) = n \log n</math>, <math>g(n) = n \sqrt n /2</math> | ||
+ | #<math>f(n) = n + \log n</math>, <math>g(n) = \sqrt n</math> | ||
+ | #<math>f(n) = 2(\log n)^2</math>, <math>g(n) = \log n + 1</math> | ||
+ | #<math>f(n) = 4n\log n + n</math>, <math>g(n) = (n^2 - n)/2</math> | ||
+ | |||
+ | |||
+ | :[[2.11]] | ||
:2.12 | :2.12 |
Revision as of 18:58, 3 September 2020
Contents
Algorithm Analysis
Program Analysis
- 2.1. What value is returned by the following function? Express your answer as a function of [math]\displaystyle{ n }[/math]. Give the worst-case running time using the Big Oh notation.
mystery(n) r:=0 for i:=1 to n-1 do for j:=i+1 to n do for k:=1 to j do r:=r+1 return(r)
- 2.2. What value is returned by the following function? Express your answer as a function of [math]\displaystyle{ n }[/math]. Give the worst-case running time using Big Oh notation.
pesky(n) r:=0 for i:=1 to n do for j:=1 to i do for k:=j to i+j do r:=r+1 return(r)
- 2.3. What value is returned by the following function? Express your answer as a function of [math]\displaystyle{ n }[/math]. Give the worst-case running time using Big Oh notation.
prestiferous(n) r:=0 for i:=1 to n do for j:=1 to i do for k:=j to i+j do for l:=1 to i+j-k do r:=r+1 return(r)
- 2.4. What value is returned by the following function? Express your answer as a function of [math]\displaystyle{ n }[/math]. Give the worst-case running time using Big Oh notation.
conundrum([math]\displaystyle{ n }[/math]) [math]\displaystyle{ r:=0 }[/math] for [math]\displaystyle{ i:=1 }[/math] to [math]\displaystyle{ n }[/math] do for [math]\displaystyle{ j:=i+1 }[/math] to [math]\displaystyle{ n }[/math] do for [math]\displaystyle{ k:=i+j-1 }[/math] to [math]\displaystyle{ n }[/math] do [math]\displaystyle{ r:=r+1 }[/math] return([math]\displaystyle{ r }[/math])
- 2.6. Suppose the following algorithm is used to evaluate the polynomial
- [math]\displaystyle{ p(x)=a_n x^n +a_{n-1} x^{n-1}+ \ldots + a_1 x +a_0 }[/math]
[math]\displaystyle{ p:=a_0; }[/math] [math]\displaystyle{ xpower:=1; }[/math] for [math]\displaystyle{ i:=1 }[/math] to [math]\displaystyle{ n }[/math] do [math]\displaystyle{ xpower:=x*xpower; }[/math] [math]\displaystyle{ p:=p+a_i * xpower }[/math] end
- How many multiplications are done in the worst-case? How many additions?
- How many multiplications are done on the average?
- Can you improve this algorithm?
- 2.7. Prove that the following algorithm for computing the maximum value in an array [math]\displaystyle{ A[1..n] }[/math] is correct.
max(A) [math]\displaystyle{ m:=A[1] }[/math] for [math]\displaystyle{ i:=2 }[/math] to n do if [math]\displaystyle{ A[i] \gt m }[/math] then [math]\displaystyle{ m:=A[i] }[/math] return (m)
Big Oh
- 2.8. #Is [math]\displaystyle{ 2^{n+1} = O (2^n) }[/math]?
- Is [math]\displaystyle{ 2^{2n} = O(2^n) }[/math]?
- 2.9. For each of the following pairs of functions, either [math]\displaystyle{ f(n ) }[/math] is in [math]\displaystyle{ O(g(n)) }[/math], [math]\displaystyle{ f(n) }[/math] is in [math]\displaystyle{ \Omega(g(n)) }[/math], or [math]\displaystyle{ f(n)=\Theta(g(n)) }[/math]. Determine which relationship is correct and briefly explain why.
- [math]\displaystyle{ f(n)=\log n^2 }[/math]; [math]\displaystyle{ g(n)=\log n }[/math] + [math]\displaystyle{ 5 }[/math]
- [math]\displaystyle{ f(n)=\sqrt n }[/math]; [math]\displaystyle{ g(n)=\log n^2 }[/math]
- [math]\displaystyle{ f(n)=\log^2 n }[/math]; [math]\displaystyle{ g(n)=\log n }[/math]
- [math]\displaystyle{ f(n)=n }[/math]; [math]\displaystyle{ g(n)=\log^2 n }[/math]
- [math]\displaystyle{ f(n)=n \log n + n }[/math]; [math]\displaystyle{ g(n)=\log n }[/math]
- [math]\displaystyle{ f(n)=10 }[/math]; [math]\displaystyle{ g(n)=\log 10 }[/math]
- [math]\displaystyle{ f(n)=2^n }[/math]; [math]\displaystyle{ g(n)=10 n^2 }[/math]
- [math]\displaystyle{ f(n)=2^n }[/math]; [math]\displaystyle{ g(n)=3^n }[/math]
- 2.10. For each of the following pairs of functions [math]\displaystyle{ f(n) }[/math] and [math]\displaystyle{ g(n) }[/math], determine whether [math]\displaystyle{ f(n) = O(g(n)) }[/math], [math]\displaystyle{ g(n) = O(f(n)) }[/math], or both.
- [math]\displaystyle{ f(n) = (n^2 - n)/2 }[/math], [math]\displaystyle{ g(n) =6n }[/math]
- [math]\displaystyle{ f(n) = n +2 \sqrt n }[/math], [math]\displaystyle{ g(n) = n^2 }[/math]
- [math]\displaystyle{ f(n) = n \log n }[/math], [math]\displaystyle{ g(n) = n \sqrt n /2 }[/math]
- [math]\displaystyle{ f(n) = n + \log n }[/math], [math]\displaystyle{ g(n) = \sqrt n }[/math]
- [math]\displaystyle{ f(n) = 2(\log n)^2 }[/math], [math]\displaystyle{ g(n) = \log n + 1 }[/math]
- [math]\displaystyle{ f(n) = 4n\log n + n }[/math], [math]\displaystyle{ g(n) = (n^2 - n)/2 }[/math]
- 2.12
- 2.13
- 2.14
- 2.15
- 2.16
- 2.17
- 2.18
- 2.19
- 2.20
- 2.21
- 2.22
- 2.23
- 2.24
- 2.25
- 2.26
- 2.27
- 2.28
- 2.29
- 2.30
- 2.31
- 2.32
- 2.33
- 2.34
- 2.35
- 2.36
Summations
- 2.37
- 2.38
- 2.39
- 2.40
- 2.41
- 2.42
- 2.43
Logartihms
- 2.44
- 2.45
- 2.46
- 2.47
Interview Problems
- 2.48
- 2.49
- 2.50
- 2.51
- 2.52
- 2.53
- 2.54
- 2.55
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