Difference between revisions of "TADM2E 6.7"

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m (Part B)
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A -1-> B
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A -1 B
B -1-> C
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B -1 C
A -3-> C
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A -1 C
 
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</pre>
  

Latest revision as of 00:48, 1 August 2020

Part A

Probably yes. Using Kruskal's algorithm, you'll still get the same insertion order of edges, regardless of how much you add or subtract from the edge weighting.


Part B

No. Example would be the following graph:

A -1 B
B -1 C
A -1 C

Shortest path from A to C is A->B->C.

If we increase all weights by two, shortest path will change to A->C