Difference between revisions of "TADM2E 3.12"

From Algorithm Wiki
Jump to: navigation, search
m
m
 
(One intermediate revision by one other user not shown)
Line 4: Line 4:
 
## If <math>bb(R/\{x_i\})</math> is True then <math>R:=R/\{x_i\}</math>
 
## If <math>bb(R/\{x_i\})</math> is True then <math>R:=R/\{x_i\}</math>
 
When this iteration is finished R will be subset of S that adds up to k.
 
When this iteration is finished R will be subset of S that adds up to k.
 +
 +
Above solution works even when there are multiple subsets that add up to k.

Latest revision as of 08:59, 26 December 2019

Let's put into the black box whole set $ S=\{x_i\}_{i=1}^n $. If $ bb(S) $ is True, then such a subset exists and we can go on:

  1. R:=S
  2. for i:=1 to n do
    1. If $ bb(R/\{x_i\}) $ is True then $ R:=R/\{x_i\} $

When this iteration is finished R will be subset of S that adds up to k.

Above solution works even when there are multiple subsets that add up to k.