Difference between revisions of "TADM2E 1.9"
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− | '' | + | '''n = 1''' |
+ | |||
+ | The single-element List is sorted. | ||
+ | |||
+ | |||
+ | '''Assume''' the algorithm is true for '''n<=k''' | ||
+ | |||
+ | i.e., | ||
+ | for i from k to 1 | ||
+ | for j from 1 to i − 1 | ||
+ | if (A[j] > A[j + 1]) | ||
+ | swap the values of A[j] and A[j + 1] | ||
+ | |||
+ | produces a sorted list[1...k]. | ||
+ | |||
+ | |||
+ | Let '''n = k+1''' | ||
+ | |||
+ | for i from k+1 to 1 | ||
+ | for j from 1 to i − 1 | ||
+ | if (A[j] > A[j + 1]) | ||
+ | swap the values of A[j] and A[j + 1] | ||
+ | |||
+ | Here, the inner loop (having counter j) just "bubbles out" the maximum element to the i-th position in the list. | ||
+ | |||
+ | So, in the first iteration with i = k+1 , on the completion of the inner loop, A[k+1] contains the maximum element of the list. | ||
+ | |||
+ | At this point, i = k and we are left with the task of sorting a k-element list which is already assumed to be performed correctly by the algorithm. | ||
+ | |||
+ | After the completion of all the iterations we have : | ||
+ | |||
+ | '''(i)''' A k-element sorted list (ascending order) : | ||
+ | |||
+ | A[1] < A[2] < A[3] <......... < A[k] | ||
+ | |||
+ | '''(ii)''' Also we have A[k+1] as the maximum element of the list. This implies A[k] < A[k+1] | ||
+ | |||
+ | |||
+ | From '''(i)''' and '''(ii)''' we get | ||
+ | |||
+ | A[1] < A[2] < A[3] <......... < A[k] < A[k+1] | ||
+ | |||
+ | which is a sorted list[1...(k+1)]. | ||
+ | |||
+ | '''QED''' | ||
+ | |||
+ | --[[User:Aroonalok|Aroonalok]] 23:29, 16 August 2013 (EDT)Aroonalok |
Revision as of 13:34, 23 July 2020
n = 1
The single-element List is sorted.
Assume the algorithm is true for n<=k
i.e.,
for i from k to 1 for j from 1 to i − 1 if (A[j] > A[j + 1]) swap the values of A[j] and A[j + 1]
produces a sorted list[1...k].
Let n = k+1
for i from k+1 to 1 for j from 1 to i − 1 if (A[j] > A[j + 1]) swap the values of A[j] and A[j + 1]
Here, the inner loop (having counter j) just "bubbles out" the maximum element to the i-th position in the list.
So, in the first iteration with i = k+1 , on the completion of the inner loop, A[k+1] contains the maximum element of the list.
At this point, i = k and we are left with the task of sorting a k-element list which is already assumed to be performed correctly by the algorithm.
After the completion of all the iterations we have :
(i) A k-element sorted list (ascending order) :
A[1] < A[2] < A[3] <......... < A[k]
(ii) Also we have A[k+1] as the maximum element of the list. This implies A[k] < A[k+1]
From (i) and (ii) we get
A[1] < A[2] < A[3] <......... < A[k] < A[k+1]
which is a sorted list[1...(k+1)].
QED
--Aroonalok 23:29, 16 August 2013 (EDT)Aroonalok