Difference between revisions of "TADM2E 2.19"
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− | + | <math> | |
+ | ({1}/{3})^n < | ||
+ | 6 < | ||
+ | \log \log n < | ||
+ | \log n = \ln n < | ||
+ | (\log n)^2 < | ||
+ | n^{\frac{1}{3}} + \log n < | ||
+ | \sqrt{n} < | ||
+ | \frac{n}{\log n}< | ||
+ | n < | ||
+ | n \log n < | ||
+ | n^2 = n^2 + \log n < | ||
+ | n^3 < | ||
+ | n - n^3 + 7n^5 < | ||
+ | ({3}/{2})^n < 2^n < | ||
+ | n! | ||
+ | </math> |
Latest revision as of 01:03, 1 August 2020
$ ({1}/{3})^n < 6 < \log \log n < \log n = \ln n < (\log n)^2 < n^{\frac{1}{3}} + \log n < \sqrt{n} < \frac{n}{\log n}< n < n \log n < n^2 = n^2 + \log n < n^3 < n - n^3 + 7n^5 < ({3}/{2})^n < 2^n < n! $