Difference between revisions of "TADM2E 1.21"
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(Another approach) |
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(1000/3 + 1000/4)/2 ≈ (333+250) = 583/2 ≈ 290 | (1000/3 + 1000/4)/2 ≈ (333+250) = 583/2 ≈ 290 | ||
d) About 12 days (240 + 48) | d) About 12 days (240 + 48) | ||
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| + | Another approach: | ||
| + | a) There are 3600s in an hour | ||
| + | b) 3600s goes into 10,000s ≈ 3 hours | ||
| + | c) multiply 3 with 100 = 300 hours (since 10,000s is 100 times less than 1,000,000) | ||
| + | d) 24h goes into 30h ≈ 1.2 day | ||
| + | e) multiply 1.2 by 10 = 12 days (since 30h is 10 times less than 300) | ||
[[introduction-TADM2E|Back to ''Introduction ...'']] | [[introduction-TADM2E|Back to ''Introduction ...'']] | ||
Latest revision as of 06:12, 26 January 2020
1 million seconds = 277.777778 hours
1 million seconds = 11.5740741 days
Possible approach:
a) There are 3600s in an hour b) Eliminating the thousands, we get 1000 / 3.6 c) 3.6 is about half-way between 3 and 4, thus the result is about (1000/3 + 1000/4)/2 ≈ (333+250) = 583/2 ≈ 290 d) About 12 days (240 + 48)
Another approach:
a) There are 3600s in an hour b) 3600s goes into 10,000s ≈ 3 hours c) multiply 3 with 100 = 300 hours (since 10,000s is 100 times less than 1,000,000) d) 24h goes into 30h ≈ 1.2 day e) multiply 1.2 by 10 = 12 days (since 30h is 10 times less than 300)
