Difference between revisions of "TADM2E 3.12"
From Algorithm Wiki
Manish.khkr (talk | contribs) m |
|||
| Line 5: | Line 5: | ||
When this iteration is finished R will be subset of S that adds up to k. | When this iteration is finished R will be subset of S that adds up to k. | ||
| − | + | Above solution works even when there are multiple subsets that add up to k. | |
Latest revision as of 08:59, 26 December 2019
Let's put into the black box whole set $ S=\{x_i\}_{i=1}^n $. If $ bb(S) $ is True, then such a subset exists and we can go on:
- R:=S
- for i:=1 to n do
- If $ bb(R/\{x_i\}) $ is True then $ R:=R/\{x_i\} $
When this iteration is finished R will be subset of S that adds up to k.
Above solution works even when there are multiple subsets that add up to k.
