Difference between revisions of "TADM2E 8.17"
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Latest revision as of 00:49, 1 August 2020
Consider the following example:
G | G | G | G |
G | B | G | G |
G | G | G | G |
There are four possible routes that avoid the bad intersection at (1, 1): DDRRR, RRDDR, RRDRD and RRRDD. We can start at the top-left and fill each square with the possible number of routes that lead to it:
1 | ? | ? | ? |
? | B | ? | ? |
? | ? | ? | ? |
1 | 1 | ? | ? |
1 | B | ? | ? |
? | ? | ? | ? |
1 | 1 | 1 | ? |
1 | B | ? | ? |
1 | ? | ? | ? |
1 | 1 | 1 | 1 |
1 | B | 1 | ? |
1 | 1 | ? | ? |
1 | 1 | 1 | 1 |
1 | B | 1 | 2 |
1 | 1 | 2 | ? |
1 | 1 | 1 | 1 |
1 | B | 1 | 2 |
1 | 1 | 2 | 4 |
Implementation in Perl:
#!/usr/bin/perl use warnings; use strict; sub count_paths { my @bad = @_; my $nr = @bad; my $nc = @{$bad[0]}; my @paths = map { [ map { 0 } @{$bad[0]} ] } @bad; for my $r (0 .. $nr - 1) { for my $c (0 .. $nc - 1) { next if $bad[$r][$c]; my $np = $r == 0 && $c == 0 ? 1 : 0; $np += $paths[$r - 1][$c] if $r > 0 && !$bad[$r - 1][$c]; $np += $paths[$r] [$c - 1] if $c > 0 && !$bad[$r] [$c - 1]; $paths[$r][$c] = $np; } } return $paths[$nr - 1][$nc - 1]; } my @bad = ( [0,0,0,0], [0,1,0,0], [0,0,0,0]); my $np = count_paths @bad; print $np, "\n";