Difference between revisions of "TADM2E 2.11"
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+ | because | ||
+ | <math> n^2 <= 2^n </math> for every n greater than 4 . | ||
+ | Hence, we can say that <math> n^2 < = C* 2^n </math> for every n>=4 and so <math> n^2 = O(2^n)</math>. | ||
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+ | Return to [[Algo-analysis-TADM2E]] ... |
Latest revision as of 00:55, 1 August 2020
because $ n^2 <= 2^n $ for every n greater than 4 . Hence, we can say that $ n^2 < = C* 2^n $ for every n>=4 and so $ n^2 = O(2^n) $.
Return to Algo-analysis-TADM2E ...