Difference between revisions of "TADM2E 2.11"
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Latest revision as of 00:55, 1 August 2020
because $ n^2 <= 2^n $ for every n greater than 4 . Hence, we can say that $ n^2 < = C* 2^n $ for every n>=4 and so $ n^2 = O(2^n) $.
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