Difference between revisions of "TADM2E 2.19"
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Kelvinjhwong (talk | contribs) (Changed "({3}/{2})^n = 2^n" to "({3}/{2})^n < 2^n") |
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| Line 13: | Line 13: | ||
n^3 < | n^3 < | ||
n - n^3 + 7n^5 < | n - n^3 + 7n^5 < | ||
| − | ({3}/{2})^n | + | ({3}/{2})^n < 2^n < |
n! | n! | ||
</math> | </math> | ||
Revision as of 06:14, 27 November 2018
$ ({1}/{3})^n < 6 < \log \log n < \log n = \ln n < (\log n)^2 < n^{\frac{1}{3}} + \log n < \sqrt{n} < \frac{n}{\log n}< n < n \log n < n^2 = n^2 + \log n < n^3 < n - n^3 + 7n^5 < ({3}/{2})^n < 2^n < n! $
