Difference between revisions of "TADM2E 1.1"

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<math>a + b < \min(a,b) \Leftrightarrow a < 0 \and b < 0</math>
  
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----
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If both ''a'' and ''b'' are negative, <math>a + b < min(a, b)</math>. For example
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      <math>a = -5</math>
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      <math>b = -7</math>
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      <math>a+ b = -5 + (-7) = -12</math>
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      <math>min(-5, -7) = -7</math>
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[[introduction-TADM2E|Back to ''Introduction ...'']]

Revision as of 13:36, 23 July 2020

$ a + b < \min(a,b) \Leftrightarrow a < 0 \and b < 0 $


If both a and b are negative, $ a + b < min(a, b) $. For example

     $ a = -5 $
     $ b = -7 $
     $ a+ b = -5 + (-7) = -12 $
     $ min(-5, -7) = -7 $


Back to Introduction ...