Difference between revisions of "TADM2E 3.1"
From Algorithm Wiki
(Recovering wiki) |
(No difference)
|
Revision as of 18:13, 11 September 2014
You just need to maintain a count, like so:
<pre>
public static boolean isBalanced(String str) { int count = 0;
for (int i = 0, n = str.length(); i < n; i++) { switch (str.charAt(i)) { case '(': count++; break; case ')': count--; break; default: throw new IllegalArgumentException(); }
if (count < 0) { System.out.println("Imbalance at index " + i); return false; } }
if (count != 0) { System.out.println("Imbalance at index " + (str.length() - 1)); return false; }
return true; }
</pre>
Another Approach to use stack in-order to solve this problem;
A. Read the string from left to right as CHR B. Keep pushing CHR until CHR is not ")" 1) Pop from stack once CHR == ")" if poped element is NOT "(" return FAlse Repeat A
--Max 07:18, 16 June 2010 (EDT)