Difference between revisions of "TADM2E 2.19"

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(Recovering wiki)
(Changed "({3}/{2})^n = 2^n" to "({3}/{2})^n < 2^n")
Line 13: Line 13:
 
n^3 <
 
n^3 <
 
n - n^3 + 7n^5 <
 
n - n^3 + 7n^5 <
({3}/{2})^n = 2^n <
+
({3}/{2})^n < 2^n <
 
n!
 
n!
 
</math>
 
</math>

Revision as of 06:14, 27 November 2018

$ ({1}/{3})^n < 6 < \log \log n < \log n = \ln n < (\log n)^2 < n^{\frac{1}{3}} + \log n < \sqrt{n} < \frac{n}{\log n}< n < n \log n < n^2 = n^2 + \log n < n^3 < n - n^3 + 7n^5 < ({3}/{2})^n < 2^n < n! $