Talk:TADM2E 3.11
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Revision as of 00:01, 6 April 2015 by SriPrasanna (talk | contribs)
For the answer given in part 2, the space required seems to be the sum from 1 to n of n which is n(n+1)/2. This gives O(n**2) for space requirements. Doesn't it?
Why cant we just sort the input (array)? Will this not mean the smallest number between x and y is always x?
