TADM2E 2.11
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because <math> n^2 <= 2^n </math> for every n greater than 4 . Hence, we can say that <math> n^2 < = C* 2^n </math> for every n>=4 and so <math> n^2 = O(2^n)</math>.
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because <math> n^2 <= 2^n </math> for every n greater than 4 . Hence, we can say that <math> n^2 < = C* 2^n </math> for every n>=4 and so <math> n^2 = O(2^n)</math>.
Return to Algo-analysis-TADM2E ...